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    <title>Comments on snippet: 'Find and replace characters in a loop'</title>
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    <link>https://ipv6.snipplr.com/</link>
    <lastBuildDate>Wed, 22 Apr 2026 05:34:20 +0000</lastBuildDate>
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      <title>MeganCarol302 said on 23/Sep/2022</title>
      <link>https://ipv6.snipplr.com/view/40508/find-and-replace-characters-in-a-loop</link>
      <description>&lt;p&gt;Your blogs stuff is purely enough for me personally.	&lt;a href="https://designzen.medium.com/the-difference-between-logo-design-and-branding-ba0e6941bcf7"&gt;top website design companies&lt;/a&gt;&lt;/p&gt;</description>
      <pubDate>Fri, 23 Sep 2022 06:05:44 UTC</pubDate>
      <guid>https://ipv6.snipplr.com/view/40508/find-and-replace-characters-in-a-loop</guid>
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      <title>AlyssaLauren8293 said on 12/Nov/2022</title>
      <link>https://ipv6.snipplr.com/view/40508/find-and-replace-characters-in-a-loop</link>
      <description>&lt;p&gt;jQuery's `.replaceWith()` function can be used to find and replace characters in a loop. To use this function, simply pass in the &lt;a href="https://mycbdfaq.com"&gt;Buy CBD&lt;/a&gt; characters you wish to find as the first argument, and the characters you wish to replace them with as the second argument. You can also pass in a function as the second argument, which will be executed if a match is found.&lt;/p&gt;</description>
      <pubDate>Sat, 12 Nov 2022 11:13:25 UTC</pubDate>
      <guid>https://ipv6.snipplr.com/view/40508/find-and-replace-characters-in-a-loop</guid>
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