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at June 2, 2012 00:20 by weilawei
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def xor_hash(a_value, block_size=16): value_size = len(a_value) padding = value_size % block_size padding = 0 if padding == 0 else block_size - padding value_size += padding if (padding != 0): a_value += b'\x00' * padding retval = bytearray(bytes(block_size)) for a_block in range(1, value_size, block_size): a_block = a_value[(a_block-1):(a_block+block_size-1)] for i in range(0, block_size): retval[i] ^= a_block[i] return retval if (__name__ == "__main__"): import sys a_value = bytearray(' '.join(sys.argv[1:]), encoding="utf-8") a_hash = xor_hash(a_value) print(''.join(["%0.2x" % a_byte for a_byte in a_hash]))
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This is a simple hash that pads its input to the block size and XORs every block together. Output is in hexadecimal octets. Probability of collisions is extremely high and they are easy to calculate, although the function is one-way, so this is more (though, not very) useful as a checksum.
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Simple XOR Hash
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Python