Posted By

mloberg on 10/22/10

Tagged

twitter

Versions (?)

Last Edited at 10/22/10 01:36am

Statistics

Viewed 532 times

Favorited by 1 user(s)

Related snippets

Display Latest Tweets JavaScript

/ Published in: JavaScript

Display the latest tweets of a user using JavaScript. Not really a recommended way. If Twitter is slow, your site will load slow. I would recommend using my PHP implementation instead. It will not hang your site if Twitter is not working.

Highlighted TextExpand

<h3>Recent Twitter Updates</h3>
<div id="twitter_update_list"></div>
<script src="twitter.js"></script> 

<script src="http://twitter.com/statuses/user_timeline/username.json?callback=twitterCallback2&amp;count=10"></script>
<p><a href="http://twitter.com/username">Follow me</a></p>

//The JavaScript file
function twitterCallback2(twitters) {
  var statusHTML = [];
  for (var i=0; i<twitters.length; i++){
    var username = twitters[i].user.screen_name;
    var status = twitters[i].text.replace(/((https?|s?ftp|ssh)\:\/\/[^"\s\<\>]*[^.,;'">\:\s\<\>\)\]\!])/g, function(url) {
      return '<a href="'+url+'">'+url+'</a>';
    }).replace(/\B@([_a-z0-9]+)/ig, function(reply) {
      return  reply.charAt(0)+'<a href="http://twitter.com/'+reply.substring(1)+'">'+reply.substring(1)+'</a>';
    });
    statusHTML.push('<li><span>'+status+'</span> <a style="font-size:85%" href="http://twitter.com/'+username+'/statuses/'+twitters[i].id+'">'+relative_time(twitters[i].created_at)+'</a></li>');
  }
  document.getElementById('twitter_update_list').innerHTML = statusHTML.join('');
}

function relative_time(time_value) {
  var values = time_value.split(" ");
  time_value = values[1] + " " + values[2] + ", " + values[5] + " " + values[3];
  var parsed_date = Date.parse(time_value);
  var relative_to = (arguments.length > 1) ? arguments[1] : new Date();
  var delta = parseInt((relative_to.getTime() - parsed_date) / 1000);
  delta = delta + (relative_to.getTimezoneOffset() * 60);

if (delta < 60) {
    return 'less than a minute ago';
  } else if(delta < 120) {
    return 'about a minute ago';
  } else if(delta < (60*60)) {
    return (parseInt(delta / 60)).toString() + ' minutes ago';
  } else if(delta < (120*60)) {
    return 'about an hour ago';
  } else if(delta < (24*60*60)) {
    return 'about ' + (parseInt(delta / 3600)).toString() + ' hours ago';
  } else if(delta < (48*60*60)) {
    return '1 day ago';
  } else {
    return (parseInt(delta / 86400)).toString() + ' days ago';
  }
}

Report this snippet Tweet

Comments

Subscribe to comments

Comment:

You need to login to post a comment.