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Revision: 10256
at December 14, 2008 17:21 by resurge
Updated Code 
try {
	File jarFile = new File(Main.class.getProtectionDomain().getCodeSource().getLocation().toURI());
} catch (URISyntaxException e) {
	//do some error handling here
}

Revision: 10255
at December 14, 2008 17:18 by resurge
Initial Code 
try {
	File jarFile = new File(Main.class.getProtectionDomain().getCodeSource().getLocation().toURI());
} catch (URISyntaxException e) {
	e.printStackTrace();
}
Initial URL 
http://www.velocityreviews.com/forums/t147526-how-to-get-jar-file-name.html
Initial Description 
The returned file will either contain the folder from where your program is running or the executable jar file, if your program is an executable jar.

I'm using `Main.class` because this code is in my main method (which is in the class 'Main'). You can replace `Main.class` by `getClass()` if you want to use this code in a non-static method.
Initial Title 
Get active execution location
Initial Tags 
java
Initial Language 
Java