try {
	File jarFile = new File(Main.class.getProtectionDomain().getCodeSource().getLocation().toURI());
} catch (URISyntaxException e) {
	//do some error handling here
}

try {
	File jarFile = new File(Main.class.getProtectionDomain().getCodeSource().getLocation().toURI());
} catch (URISyntaxException e) {
	e.printStackTrace();
}

http://www.velocityreviews.com/forums/t147526-how-to-get-jar-file-name.html

The returned file will either contain the folder from where your program is running or the executable jar file, if your program is an executable jar.

I'm using `Main.class` because this code is in my main method (which is in the class 'Main'). You can replace `Main.class` by `getClass()` if you want to use this code in a non-static method.

Get active execution location

java

Java