Revision: 11221
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at January 28, 2009 12:44 by aadsm
Initial Code
function ajax(url, fn, async) { var xmlhttp = new XMLHttpRequest(); if ( async ) { xmlhttp.onreadystatechange = function() { if ( xmlhttp.readyState == 4 && xmlhttp.status == 200 ) { fn(xmlhttp); } } } xmlhttp.open("GET", url, async); xmlhttp.send(null); if ( !async ) { fn(xmlhttp); } }
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Ajax simple call
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ajax
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JavaScript