function countdays($d)
{
 $olddate =  substr($d, 4);
 $newdate = date(Y) ."".$olddate;
 $nextyear = date(Y)+1 ."".$olddate;
 
    if($newdate > date("Y-m-d"))
    {
    $start_ts = strtotime($newdate);
    $end_ts = strtotime(date("Y-m-d"));
    $diff = $end_ts - $start_ts;
    $n = round($diff / 86400);
    $return = substr($n, 1);
    return $return;
    }
    else
    {
    $start_ts = strtotime($nextyear);
    $end_ts = strtotime(date("Y-m-d"));
    $diff = $end_ts - $start_ts;
    $n = round($diff / 86400);
    $return = substr($n, 1);
    return $return;

    }

}

I made this script to count the days until a birthday, the birthdays are stored in mysql with the year intact YYYY-MM-DD, so this function strips the first 4 chars, and adds the current year, if the date has already passed it adds the next year and counts for that.

Count days until date

php, date

PHP