Revision: 17065
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at August 21, 2009 16:20 by jcroom
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function countdays($d) { $olddate = substr($d, 4); $newdate = date(Y) ."".$olddate; $nextyear = date(Y)+1 ."".$olddate; if($newdate > date("Y-m-d")) { $start_ts = strtotime($newdate); $end_ts = strtotime(date("Y-m-d")); $diff = $end_ts - $start_ts; $n = round($diff / 86400); $return = substr($n, 1); return $return; } else { $start_ts = strtotime($nextyear); $end_ts = strtotime(date("Y-m-d")); $diff = $end_ts - $start_ts; $n = round($diff / 86400); $return = substr($n, 1); return $return; } }
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I made this script to count the days until a birthday, the birthdays are stored in mysql with the year intact YYYY-MM-DD, so this function strips the first 4 chars, and adds the current year, if the date has already passed it adds the next year and counts for that.
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Count days until date
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php, date
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PHP