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Revision: 18383
at September 29, 2009 11:59 by laurenceosx


Updated Code
f = open('test.zip', 'rb')
		
for data in iter( lambda: f.read(1024) , ''):
    pass # do stuff

# or without lambda

f = open('really_big_file.dat')
def read1k():
    return f.read(1024)

for piece in iter(read1k, ''):
    process_data(piece)

Revision: 18382
at September 29, 2009 11:58 by laurenceosx


Updated Code
f = open('test.zip', 'rb')
		
for data in iter( lambda: f.read(1024) , ''):
    pass # do stuff

#########################################

f = open('really_big_file.dat')
def read1k():
    return f.read(1024)

for piece in iter(read1k, ''):
    process_data(piece)

Revision: 18381
at September 29, 2009 11:39 by laurenceosx


Initial Code
f = open('really_big_file.dat')
def read1k():
    return f.read(1024)

for piece in iter(read1k, ''):
    process_data(piece)

Initial URL
http://stackoverflow.com/questions/519633/lazy-method-for-reading-big-file-in-python

Initial Description

                                

Initial Title
Lazy Method for Reading Big File in Python?

Initial Tags
python

Initial Language
Python