Advanced Search

Return to Snippet

Revision: 241
at July 6, 2006 02:57 by goodkail
Initial Code 
select distinct pt_services.service_bezeichnungen, pt_class_services.class_services_name, count(*) as total
from service 
inner join pt_services  
on service.id_pt_service = pt_services.id_pt_service
inner join pt_class_services
on service.id_class_services = pt_class_services.id_class_services
group by pt_services.id_pt_service, pt_class_services.id_class_services;
Initial URL 

                                

                                                            

                                    

                                        

                                        Initial Description
                                        

                                    

                                    

                                

                                                            

                                    

                                        

                                        Initial Title
                                        

                                    

                                    
select count distinct

                                

                                                            

                                    

                                        

                                        Initial Tags
                                        

                                    

                                    

                                

                                                            

                                    

                                        

                                        Initial Language
                                        

                                    

                                    
SQL