Revision: 25227
Updated Code
at March 24, 2010 03:01 by CaptainProton
Updated Code
Public Function isLetter(str As String) isLetter = (InStr(1, "abcdefghijklmnopqrstuvwxyz", LCase(str)) > 0) End Function
Revision: 25226
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at March 24, 2010 02:59 by CaptainProton
Initial Code
Public Function startsWithLetter(str As String) isLetter = (InStr(1, "abcdefghijklmnopqrstuvwxyz", LCase(str)) > 0) End Function
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This method checks whether a given string is a letter (no umlauts). The string should only be one character.
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isLetter(String)
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Visual Basic