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at September 8, 2010 18:25 by sukantahazra
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import libxml2 import libxslt import sys if (len(sys.argv) != 4): print "Usage: "+sys.argv[0]+" xsltfile xmlfile outputfile" sys.exit(1) styledoc = libxml2.parseFile(sys.argv[1]) style = libxslt.parseStylesheetDoc(styledoc) doc = libxml2.parseFile(sys.argv[2]) result = style.applyStylesheet(doc, None) style.saveResultToFilename(sys.argv[3], result, 0) style.freeStylesheet() doc.freeDoc() result.freeDoc()
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XSLT processing in python
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python, xml
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Python