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Revision: 34186
at October 19, 2010 02:34 by alexstone
Initial Code 
function debugVar($var = null, $prefix = null)
{
  if(is_array($var))
    echo "<pre>$prefix ", print_r($var), "</pre>";
  else
    echo "<pre>$prefix $var</pre>";
      
  exit;
}
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Debug Variable Function









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PHP