Revision: 49338
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at July 20, 2011 07:44 by BilalELMoussaoui
Initial Code
function is_leap($year){ try { $year = intval(abs($year)); if(is_numeric($year)){ if(($year % 4) === 0){ return true; } return false; }else{ throw new Exception('is_leap() exepts one param as numeric given ,'.gettype($year)); } }catch(Exception $e){ trigger_error($e->getMessage(),E_USER_ERROR); } }
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check if the year is leap
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check if the year is leap
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php
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PHP