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at June 9, 2012 08:31 by joseamirandavelez
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Public Function Split(ByVal InputText As String, Optional ByVal Delimiter As String) As Variant ' This function splits the sentence in InputText into ' words and returns a string array of the words. Each ' element of the array contains one word. ' This constant contains punctuation and characters ' that should be filtered from the input string. Const CHARS = ".!?,;:""'()[]{}|=" Dim strReplacedText As String Dim intIndex As Integer ' Replace tab characters with space characters. strReplacedText = Trim(Replace(InputText, _ vbTab, " ")) ' Filter all specified characters from the string. For intIndex = 1 To Len(CHARS) strReplacedText = Trim(Replace(strReplacedText, _ Mid(CHARS, intIndex, 1), " ")) Next intIndex ' Loop until all consecutive space characters are ' replaced by a single space character. Do While InStr(strReplacedText, " ") strReplacedText = Replace(strReplacedText, _ " ", " ") Loop ' Split the sentence into an array of words and return ' the array. If a delimiter is specified, use it. 'MsgBox "String:" & strReplacedText If Len(Delimiter) = 0 Then Split = VBA.Split(strReplacedText) Else Split = VBA.Split(strReplacedText, Delimiter) End If End Function
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Found in the internet. By default, it splits using all the characters in CHARS. Useful to get a list of words in a string.
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Alternative Split Function
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Visual Basic