Return to Snippet

Revision: 66099
at March 14, 2014 08:33 by ironcrema


Initial Code
UPDATE your_table
SET your_field = REPLACE(your_field, 'articles/updates/', 'articles/news/')
WHERE your_field LIKE '%articles/updates/%'

Initial URL


Initial Description
Replace string mysql

Initial Title
Replace String MySql

Initial Tags
replace

Initial Language
MySQL