Revision: 68751
Updated Code
at February 19, 2015 05:36 by adino
Updated Code
o=(s=' '.ord)/s;a=[o^o,o] o.upto(s-b=o+o){|x|print x,': ',(a<<a[-b]+a[-o])[-b],"\n"}
Revision: 68750
Updated Code
at February 19, 2015 04:51 by adino
Updated Code
o=(s=' '.ord)/s;a=[o^o,o] (o..s-o-o).each{|x|printf "%d: %d\n",x,a[-o];a<<a[-o-o]+a[-o]}
Revision: 68749
Initial Code
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Initial Description
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at February 19, 2015 04:31 by adino
Initial Code
o=(s=' '.ord)/s;a=[o^o,o] def f(a,o,s) return if s<x=a.size puts "#{x-o}: #{a[-o]}";f(a<<a[-o-o]+a[-o],o,s) end;f(a,o,s-o)
Initial URL
Initial Description
ruby
Initial Title
30 fibonacci number without using numbers in ruby
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Ruby