Revision: 68992
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at April 1, 2015 09:23 by BDOGG32
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​ Option Compare Text Function Get_Word(text_string As String, nth_word) As String Dim lWordCount As Long With Application.WorksheetFunction lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1 If IsNumeric(nth_word) Then nth_word = nth_word - 1 Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ .Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _ .Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _ .Find("^", .Substitute(text_string, " ", "^", nth_word)), 256)) - 2) ElseIf nth_word = "First" Then Get_Word = Left(text_string, .Find(" ", text_string) - 1) ElseIf nth_word = "Last" Then Get_Word = Mid(.Substitute(text_string, " ", "^", Len(text_string) - _ Len(.Substitute(text_string, " ", ""))), .Find("^", .Substitute(text_string, " ", "^", _ Len(text_string) - Len(.Substitute(text_string, " ", "")))) + 1, 256) End If End With End Function Function ExtractElement(Txt, n, Separator) As String ' Returns the nth element of a text string, where the elements ' are separated by a specified separator character Dim Txt1 As String, TempElement As String Dim ElementCount As Integer, i As Integer Txt1 = Txt ' If space separator, remove excess spaces If Separator = Chr(32) Then Txt1 = Application.Trim(Txt1) ' Add a separator to the end of the string (if necessary) If Right(Txt1, 1) <> Separator Then Txt1 = Txt1 & Separator ' Initialize ElementCount = 0 TempElement = "" ' Extract each element For i = 1 To Len(Txt1) If Mid(Txt1, i, 1) = Separator Then ElementCount = ElementCount + 1 If ElementCount = n Then ' Found it, so exit ExtractElement = TempElement Exit Function Else TempElement = "" End If Else TempElement = TempElement & Mid(Txt1, i, 1) End If Next i ExtractElement = "" End Function
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Two functions that can extract text from a string. Must have the Option Compare Text at the top of the module.
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Extract text from a String
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excel
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Visual Basic