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Debugging JS with GA by Yahel Carmon

/ Published in: JavaScript
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1. no need to wrap the (potentially) offending code in try/catch
2. use window.onerror:

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Copy this code and paste it in your HTML 
  1. <script>
  2. 		(function(){
  3. 		var old = window.onerror;
  4. 		window.onerror = function (msg, url, line) {
  5. 			if(typeof old==="function") { old(msg,url,line);} 
  6. 			_gaq.push(['_trackEvent', 'Error Log', msg, url+'_'+line]);
  7. 		};
  8. 		}());
  9. 		</script>
  10. 		<script type="text/javascript"> 
  11.  
  12. 		  var _gaq = _gaq || [];
  13. 		  _gaq.push(['_setAccount', 'UA-XXXXXXXXX-Y']);
  14. 		  _gaq.push(['_trackPageview']);
  15.  
  16. 		  (function() {
  17. 		    var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
  18. 		    ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
  19. 		    var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
  20. 		  })();
  21.  
  22. 		</script>

URL: http://dl.dropbox.com/u/397675/error_test.html

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