Revision: 34907
Updated Code
at November 19, 2010 07:27 by adkatrit
Updated Code
public static void main(String[] args) {
String[] arr = {"0","1","2","3"};
int len = arr.length;
for(int p= 0;p<len;p++){
for(int i=len;i-->p+1;){
System.out.print(arr[p]+arr[i]+" ");
}
}
}
Revision: 34906
Initial Code
Initial URL
Initial Description
Initial Title
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at October 30, 2010 02:21 by adkatrit
Initial Code
public static void main(String[] args) {
String[] arr = {"0","1","2","3"};
int len = arr.length;
int thresh = 1;
for(int p= 0;p<len;p++,thresh++){
//System.out.println(arr[p]);
for(int i=len;i-->thresh;){
System.out.print(arr[p]+arr[i]+" ");
}
System.out.println(p);
}
}
Initial URL
Initial Description
compare individual array elements with one another, without doing the same comparison twice (3vs2 then 2vs3). this reduces the number of iterations by roughly half. it's still O(n^2), an 1000 member array won't iterate a 1000X1000 times, it will be (1000X999)/2. efficient!! an array of 0,1,2,3 will print out the following: 01,02,03,,12,13,2,3 ENJOY MY MATHS
Initial Title
Matching elements in an array
Initial Tags
Initial Language
Java