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Matching elements in an array

/ Published in: Java
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compare individual array elements with one another, without doing the same comparison twice (3vs2 then 2vs3). this reduces the number of iterations by roughly half. it's still O(n^2), an 1000 member array won't iterate a 1000X1000 times, it will be (1000X999)/2. efficient!!
an array of 0,1,2,3 will print out the following:
01,02,03,,12,13,2,3
ENJOY MY MATHS

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  1. public static void main(String[] args) {
  2.     	String[] arr = {"0","1","2","3"};      
  3.     	  int len = arr.length;
  4.     	    	for(int p= 0;p<len;p++){
  5.     	    		for(int i=len;i-->p+1;){
  6.     	    			System.out.print(arr[p]+arr[i]+" ");
  7.     	    		}
  8.     	    	}
  9.     }

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