Posted By

sukantahazra on 09/08/10

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python
xml

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Last Edited at 09/08/10 06:25pm

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XSLT processing in python

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import libxml2
import libxslt
import sys
 
if (len(sys.argv) != 4):
        print "Usage: "+sys.argv[0]+" xsltfile xmlfile outputfile"
        sys.exit(1)
 
styledoc = libxml2.parseFile(sys.argv[1])
style = libxslt.parseStylesheetDoc(styledoc)
doc = libxml2.parseFile(sys.argv[2])
result = style.applyStylesheet(doc, None)
style.saveResultToFilename(sys.argv[3], result, 0)
style.freeStylesheet()
doc.freeDoc()
result.freeDoc()